Question

Question #8b42e

Answer 1

Mostly not possible.........................

Explanation:

This is a very hard question and I think no one could solve this question because this is listed in the list of unsolved questions in physics.

Free neutrons are unstable with a half life of 10 minutes,11 seconds .It decays via beta decay`(beta^(-) "decay" )`

Beta Decay

Beta decay is a very complicated process and involves one of the fermions,upp quarks and down quarks

As you must know a neutron is made 2 down quarks and 1 upp quark

A free neutron is not stable. The upp quark in the neutron get converted into a down neutron and a W boson. This can be represented in an equation

`"udd" rarr "uud" + W boson`

Obtaining from this equation

`u rarr "W boson"`

This means the weight of W boson

Mass of upp quark = 2.15 mega electron volts

1 `"MeV" = 1.6xx10^(-19)J`

`therefore` `2.15MeV = 2.15 xx (1.6xx10^(-19)J)`

= `3.44e-19J`

`E = mc^2`

c is speed of light

We know the energy calculate the mass

`3.44e-19 = "299,792,458/s"^2x`

Calculate x

`1.1474605e-27kg`

Some others say 2.4572e-22 kg

`therefore` Mass of W Boson = #2.4572e-22 kg - "mass of down quark" #

The W boson later decays to form an antineutrino and a electron

`"W boson" rarr "antineutrino" + "electron"`

So you can say neutrons can't say stable.After 2 neutrons being bonded there are no trineutrons nor tetraneutron and Pentaneutron.