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Answer 1 · 2017-04-27T17:43:54

Mostly not possible.........................

This is a very hard question and I think no one could solve this question because this is listed in the list of unsolved questions in physics.

Free neutrons are unstable with a half life of 10 minutes,11 seconds .It decays via beta decay $(β^{-} decay)$ $(beta^(-) "decay" )$

Beta Decay

Beta decay is a very complicated process and involves one of the fermions,upp quarks and down quarks

As you must know a neutron is made 2 down quarks and 1 upp quark

A free neutron is not stable. The upp quark in the neutron get converted into a down neutron and a W boson. This can be represented in an equation

$udd \to uud + W b o s o n$ $"udd" rarr "uud" + W boson$

Obtaining from this equation

$u \to W boson$ $u rarr "W boson"$

This means the weight of W boson

Mass of upp quark = 2.15 mega electron volts

1 $MeV = 1.6 \times 10^{- 19} J$ $"MeV" = 1.6xx10^(-19)J$

$therefore$ $2.15MeV = 2.15 xx (1.6xx10^(-19)J)$

= $3.44e-19J$

$E = mc^2$

c is speed of light

We know the energy calculate the mass

$3.44e-19 = "299,792,458/s"^2x$

Calculate x

$1.1474605e-27kg$

Some others say 2.4572e-22 kg

$therefore$ Mass of W Boson = $2.4572e-22 kg - "mass of down quark"$

The W boson later decays to form an antineutrino and a electron

$"W boson" rarr "antineutrino" + "electron"$

www.nuclear-power.net

So you can say neutrons can't say stable.After 2 neutrons being bonded there are no trineutrons nor tetraneutron and Pentaneutron.