What volume of HCl(g) is required for equivalence to a 32⋅mL volume of AgNO3(aq) at 0.08⋅mol⋅L−1 concentration?

1 Answer
anor277
Apr 27, 2017

We need an equivalent molar quantity of HCl(g)......I gets under 60⋅cm3 or under 60⋅mL.......................

Explanation:

Moles of Ag+=32×10−3L×0.08⋅mol⋅L−1=2.56×10−3⋅mol.

And thus we need an equivalent molar quantity of Cl−, and thus an equivalent molar quantity of HCl(g), which is presumed to dissolve quantitatively in water to give HCl(aq).

So we use the Ideal Gas Equation,

V=nRTP=2.56×10−3⋅mol×0.0821⋅L⋅atmK⋅mol×273⋅K1⋅atm

Note that I have used 1⋅atm to represent a pressure of 100⋅kPa, which is near enuff.

We get V=0.057⋅L=57.4⋅cm3.

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