Question #a485f

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Question #a485f

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Answer 1 · 2017-04-27T13:25:31

The new volume would be 225 mL. Half the volume at twice the pressure.

Explanation:

This behaves according to Boyle's law which tells us that the volume of a gas and its pressure are inversely proportional. That means if one is doubled, the other is reduced by a factor of two. Triple the pressure, and the volume is one-third of what it was before.

In equation form:

$P_{2} \cdot V_{2} = P_{1} \cdot V_{1}$ $P_2*V_2 = P_1*V_1$

So,

$V_{2} = \frac{P_{1} \cdot V_{1}}{P_{2}}$ $V_2 = (P_1*V_1)/P_2$

In your problem, the doubling of the pressure can be taken to mean

$\frac{P_{1}}{P_{2}} = \frac{1}{2}$ $P_1/P_2 = 1/2$

Now, the equation reads

$V_{2} = (\frac{1}{2}) V_{1}$ $V_2 = (1/2) V_1$

So, there is our result. If $V_{2}$ $V_2$ is 450, $V_{2}$ $V_2$ must be 1/2 of this.

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Question #a485f

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