If a $2.96 \cdot g$ $2.96g$ mass of potassium chloride, and a $1.92 \cdot g$ $1.92g$ mass of dioxygen gas react, what mass of $potassium chlorate$ $"potassium chlorate"$ results?

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Answer 1 · 2017-04-29T16:51:46

$x<=............5*g$

There are $x*g$ $KClO_3$ ...........

And we recover $(2.96*g)/(74.55*g*mol^-1)=0.0397*mol$ with respect to $KCl$ .

And $(1.92*g)/(15.999*g*mol^-1)=0.120*mol$ with respect to $"oxygen"$ .

Clearly, there were $0.0397$ $"mol"$ with respect to $KClO_3$ .

And thus $x$ , $"mass of potassium chlorate"$ $=$ $0.0397*molxx122.55*g*mol^-1=4.86*g$

If a 2.96*g2.96⋅g2.96*g mass of potassium chloride, and a 1.92*g1.92⋅g1.92*g mass of dioxygen gas react, what mass of "potassium chlorate"potassium chlorate"potassium chlorate" results?