What is the "VSEPR"VSEPR treatment of "hydrazine"hydrazine?

1 Answer
anor277
May 1, 2017

There are 4xx1+2xx7=18*"electrons"4×1+2×7=18⋅electrons to distribute around 6 centres........

Explanation:

And so for hydrazine, we write,

H_2ddotN-ddotNH_2; these represent 14 valence electrons, 4xxN-H, and 1xxN-N, and 2xxN lone pairs.

The remaining 4 electrons are conceived to be the inner core electrons on the nitrogen centre (i.e. the original 1s^2 sets). Anyway, we have distributed 18 electrons as required, 14 are valence electrons. Capisce?

What is the geometry about the nitrogen centres?

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