Question #06c7a

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Question #06c7a

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Answer 1 · 2017-05-03T07:42:03

We (MUST!) assume constant pressure, and $V_{2} ≅ 10 \cdot L$ $V_2~=10*L$

Explanation:

For a given quantity of constant under constant pressure:

$P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$ , and thus..............

$V_{2} = \frac{P_{1} V_{1}}{P_{1}} = \frac{15.0 \cdot L \times 1.05 \cdot a t m}{1.57 \cdot a t m} = ? ? L$ $V_2=(P_1V_1)/P_1=(15.0*Lxx1.05*atm)/(1.57*atm)=??L$ ......

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Question #06c7a

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