Given a $"molecular formula"$ of $C_4H_8O_2$ , what is the $"empirical formula"$ ?

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Answer 1 · 2017-05-04T18:22:17

Well the $"molecular formula"$ is $C_4H_8O_2$ .........

And the $"empirical formula"$ is the simplest whole number ratio that defines constituent atoms in a species, and thus...................

$"empirical formula"$ $=$ $C_2H_4O$

The molecular formula is always a whole number multiple of the empirical formula, i.e............

$"molecular formula"=nxx{"empirical formula"}$ .

To what does $n$ equal here?

Given a "molecular formula""molecular formula" of C_4H_8O_2C_4H_8O_2, what is the "empirical formula""empirical formula"?