How would we represent the reaction of $S O_{2}$ $SO_2$ with $K_{2} C r_{2} O_{7}$ $K_2Cr_2O_7$ to give $S O_{3}$ $SO_3$ ?

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How would we represent the reaction of $S O_{2}$ $SO_2$ with $K_{2} C r_{2} O_{7}$ $K_2Cr_2O_7$ to give $S O_{3}$ $SO_3$ ?

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Answer 1 · 2017-05-06T07:34:34

We would assume that the sulfur dioxide is oxidized to sulfur trioxide.

Explanation:

${I V + SO}_{2} + H_{2} O \to {V I + SO}_{3} + 2 H^{+} + 2 e^{-}$ $stackrel(IV+)"SO"_2 +H_2O rarr stackrel(VI+)"SO"_3 +2H^(+) +2e^(-)$ $(1)$ $(1)$

And dichromate is reduced to chromic ion......:

$C r_{2} O_{7}^{2 -} + 14 H^{+} + 6 e^{-} \to 2 C r^{3 +} + 7 H_{2} O$ $Cr_2O_7^(2-) +14H^(+) + 6e^(-) rarr 2Cr^(3+) + 7H_2O$ $(2)$ $(2)$

And we take $3 \times (1) + (2)$ $3xx(1)+(2)$ to eliminate the electrons:

$C r_{2} O_{7}^{2 -} + 8 H^{+} + 3 S O_{2} \to 2 C r^{3 +} + 3 S O_{3} + 4 H_{2} O$ $Cr_2O_7^(2-) +8H^(+) + 3SO_2 rarr 2Cr^(3+) + 3SO_3 + 4H_2O$

Are charge and mass balanced? If the answer is no then we cannot accept the reaction. Industrially, the oxidant is oxygen gas. I do not know if the reaction would proceed as written.

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How would we represent the reaction of $S O_{2}$ $SO_2$ with $K_{2} C r_{2} O_{7}$ $K_2Cr_2O_7$ to give $S O_{3}$ $SO_3$ ?

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Explanation:

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How would we represent the reaction of SO_2SO2SO_2 with K_2Cr_2O_7K2Cr2O7K_2Cr_2O_7 to give SO_3SO3SO_3?

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How would we represent the reaction of $S O_{2}$ $SO_2$ with $K_{2} C r_{2} O_{7}$ $K_2Cr_2O_7$ to give $S O_{3}$ $SO_3$ ?