Question #80a54

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Question #80a54

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Answer 1 · 2017-05-07T16:57:27

You have copied the question wrong.

$V O_{2}$ $VO_2$ is a not an ion. It is a compound formed by the following reaction and compounds have a charge of 0. It forms $V O^{+ 2}$ $VO^(+2)$ when dissolved in non-oxidising acids such as $H C l$ $HCl$

$V_{2} O_{5} + V_{2} O_{3} \to 4 V O_{2}$ $V_2O_5 + V_2O_3 → 4 VO_2$

So actually the equation is

$x + ((- 2) + (- 2)) = 0$ $x + ((-2) + (-2)) = 0$
$x + (- 4) = 0$ $x + (-4) = 0$
$x = 4$ $x = 4$

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Question #80a54

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