Question #be045

1 Answer
May 10, 2017

The mole fraction of "NO"_2 in the mixture is 0.791.

Explanation:

Vapour density is the density of a gas relative to that of hydrogen at the same temperature and pressure.

"Vapour density" = "density of mixture"/("density of H"_2) = "mass of mixture"/("mass of H"_2) = "molar mass of mixture"/("molar mass of H"_2) = "Molar mass of mixture"/"2.016 g/mol" = 27.6

"Molar mass of mixture" = "27.6 × 2.016 g/mol" = "55.64 g/mol"

Let x = the mole fraction of "NO"_2.

Then 1-x = the mole fraction of "N"_2"O"_4.

x × 46.01 color(red)(cancel(color(black)("g/mol"))) + (1-x) × 92.01 color(red)(cancel(color(black)("g/mol"))) = 55.64color(red)(cancel(color(black)( "g/mol")))

46.01x + 92.01(1-x) = 55.64

46.01x + 92.01 - 92.01x = 55.64

46.00x = 36.37

x = 36.37/46.00 = 0.791

The mole fraction of "NO"_2 is 0.791.