Elemental chlorine consists mainly of two isotopes: $^{35} C l$ $""^35Cl$ of $75 %$ $75%$ abundance; and $^{37} C l$ $""^37Cl$ ... What is the average atomic mass of chlorine?

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Answer 1 · 2017-05-11T07:28:40

About $35.5 \cdot amu$ $35.5*"amu"$

Atomic mass is the weighted average of the individual isotopes.

And thus average atomic mass is given by the expression:

$(0.75 \times 35 (^{35} C l) + 0.25 \times 37 (^{37} C l)) \cdot amu =$ $(0.75xx35(""^35Cl) +0.25xx37(""^37Cl))*"amu"=$

$35.5 \cdot amu$ $35.5*"amu"$

Elemental chlorine consists mainly of two isotopes: 35Cl""^35Cl of 75%75% abundance; and 37Cl""^37Cl... What is the average atomic mass of chlorine?