Question #efd49

1 Answer

See below

Explanation:

At STP, we know the following:

Temperature = "273.15 K" (0^@ "C")
Pressure = 1 "atm"

Plugging this into the ideal gas law yields:

PV = nRT

=> ("1 atm")V = n("0.0821 L"cdot"atm/mol"cdot"K")("273.15 K")

=> V = "22.414 L/mol"*(n)

Note that all units except L will cancel out, due to the dimensions of the R value

Therefore, for 1 mol of gas:

V = "22.414 L"

There you have it.

Hope that helps :)