Question

Question #efd49

Answer 1

See below

Explanation:

At STP, we know the following:

Temperature = `"273.15 K"` (`0^@ "C")`
Pressure = `1` `"atm"`

Plugging this into the ideal gas law yields:

`PV = nRT`

`=> ("1 atm")V = n("0.0821 L"cdot"atm/mol"cdot"K")("273.15 K")`

`=> V = "22.414 L/mol"*(n)`

Note that all units except `L` will cancel out, due to the dimensions of the `R` value

Therefore, for 1 mol of gas:

`V = "22.414 L"`

There you have it.

Hope that helps :)