Question

What mass of `"calcium carbide"` gives a `1*L` volume of acetylene under standard conditions?

Answer 1

This reactor uses calcium carbide as its hydrocarbon source..........

Explanation:

And follows the stoichiometric equation:

`color(blue)(Ca^(2+)[""^(-)C-=C^(-)](s) + 2H_2OrarrCa(OH)_2 + HC-=CH(g)uarr)`

We assume you want `1*L` of acetylene gas under standard conditions of temperature and pressure, which (depending on the standard) is `0` `""^@C` and `100` `kPa`

Using the Ideal Gas equation with the appropriate gas constant, we solve for `n=(PV)/(RT)`

`=color(red)(1*"bar"xx1*L)/color(red)(8.314xx10^-2*L*"bar"*K^-1*mol^-1xx273.15*K)`

`=0.0440*mol`.

And so we need a mass of ............................................

`0.0440*molxx64.1*g*mol^-1=2.81*g` with respect to `"calcium carbide"`.