Question

Question #d09f9

Answer 1

`N` is being oxidized,
`H` is being reduced.

Explanation:

Since `N_2(g)` has an oxidation state of `0` originally, and then has an oxidation state of `+3` on the products side, `N` is being oxidized.

Since `H_2(g)` has an oxidation state of `0` originally, and then has an oxidation state of `-1` on the products side, `H` is being reduced.