Question

Question #27cfc

Answer 1

ONE (1)

Explanation:

One mole of any gas at 0 deg-Celcius (=273K) and 1 atm pressure (STP) occupies 22.4 Liters.

Using Ideal Gas Law PV = nRT => V = (nRT)/(P)

For Volume of 1 mole of any gas at STP

`V_(STP) = ((1"mole")(0.08206"L-Atm"/"mole-K")(273K)(1 Atm^(-1))) = 22.4 Liters`