How does ammonium hydroxide react with sulfuric acid?

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How does ammonium hydroxide react with sulfuric acid?

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Answer 1 · 2017-05-18T21:35:10

Please notice that the anions swap places from the left side to the right side; this makes it a Double Displacement reaction.

Answer 2 · 2017-05-18T21:35:11

This is an acid base reaction...........

Explanation:

When we write $N H_{4} O H$ $NH_4OH$ , i.e. $ammonium hydroxide$ $"ammonium hydroxide"$ , we really mean $H_{3} N \cdot O H_{2}$ $H_3N*OH_2$ , i.e. aqueous ammonia. Concentrated ammonia solution in water (the type that is retailed) is approx. $15 \cdot m o l \cdot L^{- 1}$ $15*mol*L^-1$ with respect to ammonia.

Now of course, as a weak base, there is SOME ammonium ion in solution according to the following equilibrium:

$N H_{3} (a q) + H_{2} O (l) ⇌ N H_{4}^{+} + H O^{-}$ $NH_3(aq) + H_2O(l) rightleftharpoons NH_4^+ + HO^-$ ,

but the equilibrium lies to the left, and the dominant species in solution is $N H_{3} (a q)$ $NH_3(aq)$ .

And so we could rewrite the reaction as:

$H_{2} S O_{4} (a q) + 2 N H_{3} (a q) \to 2 N H_{4}^{+} + S O_{4}^{2 -}$ $H_2SO_4(aq) + 2NH_3(aq) rarr 2NH_4^+ + SO_4^(2-)$ .

We could isolate the salt $ammonium sulfate$ $"ammonium sulfate"$ , ${(N H_{4})}_{2} S O_{4}$ $(NH_4)_2SO_4$ from such a solution. Ammonium sulfate is a ubiquitous agricultural fertilizer.

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How does ammonium hydroxide react with sulfuric acid?

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