How many moles of oxygen molecules, $O_2$ , will react with $4.68$ mol of aluminium to produce aluminium oxide, $Al_2O_3$ ?

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Answer 1 · 2017-05-20T23:53:33

The balanced chemical equation is $2Al + 3O_2 -> 2Al_2O_3$ .

The mole ratio is $3/2$ , so $3/2xx4.68=7.02$ mol of $O_2$ will react with $4.68$ mol of Al.

How many moles of oxygen molecules, O_2O_2, will react with 4.684.68 mol of aluminium to produce aluminium oxide, Al_2O_3Al_2O_3?