What are the valence electrons in $M g C l^{+}$ $MgCl^+$ , $C O_{2}$ $CO_2$ , and $H F$ $HF$ ?

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Answer 1 · 2017-05-23T16:33:52

Well magnesium is an $alkaline earth$ $"alkaline earth"$ , i.e. a $Group 2 metal cation$ $"Group 2 metal cation"$ ....

And so for $M g C l^{+}$ $MgCl^+$ ; you possibly meant to write $M g C l_{2}$ $MgCl_2$ , i.e. $M g^{2 +} + 2 \times C l^{-}$ $Mg^(2+) + 2xxCl^-$ .

For $C O_{2}$ $CO_2$ , we have $4 + 6 + 6$ $4+6+6$ valence electrons to distribute; i.e. 8 electron pairs:

$: . . O = C = . . O :$ $:stackrel(..)O=C=stackrel(..)O:$

And for hydrogen fluoride, we have $1 + 7$ $1+7$ valence electrons, i.e. 4 electron pairs...........

$H - F$ $H-F$ .

What are the valence electrons in MgCl+MgCl^+, CO2CO_2, and HFHF?