Question #f5981

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Question #f5981

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Answer 1 · 2017-05-23T15:14:50

The oxidation number of $M n$ $Mn$ in $M n C l_{2}$ $MnCl_2$ is +2 while its oxidation number in $M n O_{2}$ $MnO_2$ is +4.

Explanation:

With a few exceptions, the oxidation number of an element is equal to its charge. In $M n C l_{2}$ $MnCl_2$ , the charge/oxidation number of the $C l$ $Cl$ atom is -1 since it is in the halogen family, and since the molecule $M n C l_{2}$ $MnCl_2$ has 2 $C l$ $Cl$ atoms, it has a -2 oxidation number. Assuming your compound is a neutral compound with no overall charge, $M n$ $Mn$ would have a +2 oxidation number in the compound.

For $M n O_{2}$ $MnO_2$ , $O$ $O$ has a -2 charge/oxidation number, so 2 $O$ $O$ atoms would have a charge of -4. This means $M n$ $Mn$ has an oxidation number of +4 in order to make the neutral compound.

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