Given two aqueous solution whose respective $p H$ $pH$ values are $6$ $6$ and $3$ $3$ , how much more acidic is one solution compared to the other?

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Given two aqueous solution whose respective $p H$ $pH$ values are $6$ $6$ and $3$ $3$ , how much more acidic is one solution compared to the other?

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Answer 1 · 2017-05-25T15:21:05

$By a factor of 1000.............$ $"By a factor of 1000............."$

Explanation:

By definition, $p H = - {log}_{10} [H_{3} O^{+}]$ $pH=-log_10[H_3O^+]$ ......

And thus when $p H = 6$ $pH=6$ , $[H_{3} O^{+}] = 10^{- 6} \cdot m o l \cdot L^{- 1}$ $[H_3O^+]=10^(-6)*mol*L^-1$

And when $p H = 3$ $pH=3$ , $[H_{3} O^{+}] = 10^{- 3} \cdot m o l \cdot L^{- 1}$ $[H_3O^+]=10^(-3)*mol*L^-1$ .

And thus there is a 1000-fold difference between the solution concentrations with respect to $[H_{3} O^{+}]$ $[H_3O^+]$ . AS always, the numerically LOWER $p H$ $pH$ corresponds to a higher concentration of $[H_{3} O^{+}]$ $[H_3O^+]$ . If we have a concentration of $[H C l] = 1.0 \cdot m o l \cdot L^{- 1}$ $[HCl]=1.0*mol*L^-1$ , what is the solution $p H$ $pH$ ?

For an undergrad discussion of $p H$ $pH$ see [this linky.](https://socratic.org/questions/ph-value-definition)

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