If there are 115.6*L115.6L of fluorine gas at "STP"STP, what is the molar quantity?

1 Answer
May 25, 2017

Approx. 5*mol5mol.................

Explanation:

The molar volume of an Ideal Gas at "STP"STP is 22.4*L22.4L, and thus number of moles ="volume of gas"/"molar volume"=volume of gasmolar volume. We assume that behaviour of F_2(g)F2(g) approaches ideality.

=(115.6*cancelL)/(22.4*cancelL*mol^-1)=5.16*1/(mol^-1)

=5.16*1/(1/(mol))=5.16*mol.

What is the mass of this quantity of gas?