How do we represent the oxidation of thiosulfate anion, S2O23 to tetrathionite, S4O26...?

1 Answer
May 27, 2017

Thiosulfate to tetrathionite...........

2S2O23S4O26+2e ;IISII12S

Explanation:

I always considered thiosulfate dianion, S2O23, to be the same as sulfate dianion, SO24, EXCEPT that one of the oxygen atoms has been replaced by congeneric sulfur. And this sulfur has PRECISELY the same oxidation state as the oxygen it replaces, i.e. IIS. The AVERAGE oxidation states is still.................................

S(II)+S(+VI)2=S(+II)

Anyway, let's try to balance the beast.

2S2O23S4O26+2e ;IISII12S

Do you agree that it is balanced with respect to mass and charge?