How do we classify the reaction, $M g (s) + C l_{2} (g) \to M g C l_{2} (s)$ $Mg(s) + Cl_2(g) rarr MgCl_2(s)$ ?

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Answer 1 · 2017-05-28T20:18:54

Well, $reaction 1$ $"reaction 1"$ is.........

Redox reactions involve a formal change in oxidation number........

And if we superscript the oxidation numbers..........

$0 Mg + {0 Cl}_{2} (g) \to + I I Mg {- I Cl}_{2}$ $stackrel(0)"Mg" +stackrel(0)"Cl"_2(g)rarrstackrel(+II)"Mg"stackrel(-I)"Cl"_2$

The metal has been (typically) oxidized, and has donated electrons to the non-metal, and thus reduced it..........

Can you write the individual half equations representing formal oxidation and reduction?

How do we classify the reaction, Mg(s) + Cl_2(g) rarr MgCl_2(s)Mg(s)+Cl2(g)→MgCl2(s)Mg(s) + Cl_2(g) rarr MgCl_2(s)?