How is the oxidation of aluminum metal by acid, hydrogen ion, represented?

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How is the oxidation of aluminum metal by acid, hydrogen ion, represented?

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Answer 1 · 2017-05-29T10:06:01

Aluminum is oxidized............

Explanation:

$A l (s) \to A l^{3 +} + 3 e^{-}$ $Al(s) rarr Al^(3+) + 3e^(-)$ $(i)$ $(i)$

And hydrogen ion is reduced............

$H^{+} + e^{-} \to \frac{1}{2} H_{2} (g)$ $H^(+) + e^(-) rarr 1/2H_2(g)$ $(i i)$ $(ii)$

And we can cross multiply the individual redox reactions to remove the electrons, which are conceptual particles, i.e. $(i) + 3 \times (i i)$ $(i)+3xx(ii)$ :

$A l (s) + 3 H^{+} \to A l^{3 +} + \frac{3}{2} H_{2} (g)$ $Al(s) +3H^(+) rarr Al^(3+) + 3/2H_2(g)$

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How is the oxidation of aluminum metal by acid, hydrogen ion, represented?

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