Question #42173

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Answer 1 · 2017-05-29T15:44:31

$10^{- pH}$ $10^(-"pH")$ is the formula for converting $pH$ $"pH"$ into $[H^{+}]$ $["H"^+]$ , the hydrogen/hydronium ion concentration of a solution.

Answer 2 · 2017-05-29T16:01:30

You use this to calculate the $[H_{3} O^{+}]$ $["H"_3"O"^+]$ of a solution (the molar concentration of hydronium/hydrogen ions in solution).

Remember that to find the $pH$ $"pH"$ from a known $[H_{3} O^{+}]$ $["H"_3"O"^+]$ , we can use the formula

$pH = - log [H_{3} O^{+}]$ $"pH" = -log["H"_3"O"^+]$

If we use the properties of logarithms, we can derive that equation from this one:

$pH = - log [H_{3} O^{+}]$ $"pH" = -log["H"_3"O"^+]$

$- pH = log [H_{3} O^{+}]$ $-"pH" = log["H"_3"O"^+]$

$10^{- pH} = [H_{3} O^{+}]$ $10^-"pH" = ["H"_3"O"^+]$