Question #f395d

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Question #f395d

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Answer 1 · 2017-05-31T11:32:59

Concentration of Phosphoric Acid decreases.

Explanation:

This is because the $O H^{-}$ $OH^-$ ions from $N a O H$ $NaOH$ ( $N a O H$ $NaOH$ $\to$ $rarr$ $N a^{+}$ $Na^+$ + $O H^{_}$ $OH^_$ ) neutralise the $H^{+}$ $H^+$ ions from $H_{3} P O_{4}$ $H_3PO_4$ (Phosphoric Acid).
The equation for the dissociation of $H_{3} P O_{4}$ $H_3PO_4$ is;
$H_{3} P O_{4}$ $H_3PO_4$ $⇌$ $rightleftharpoons$ $H_{2} P O_{4}$ $H_2PO_4$ + $H^{+}$ $H^+$
The concentration of $H^{+}$ $H^+$ ions on the right hand side of the equation therefore decreases, and the point of equilibrium shifts to the right, in order to oppose the decrease in concentration of $H^{+}$ $H^+$ ions. The point of equilibrium shifts to the right, by more $H_{3} P O_{4}$ $H_3PO_4$ dissociating, regenerating $H^{+}$ $H^+$ ions, thus decreasing the concentration of Phosphoric Acid.

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