Question #921b9

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Question #921b9

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Answer 1 · 2017-06-01T05:44:52

$P b {(N O_{3})}_{2} + C l^{-} = P b C l_{2} + N O_{3}^{-}$ $Pb(NO_3)_2 + Cl^(-) = PbCl_2 + NO_3^-$

Explanation:

Cl doesn't exist as single atom, it can exist as $C l^{-}$ $Cl^-$ that is an anion quite stable. It can react with the cations: $A g^{+}, H g_{2}^{2 +}$ $Ag^+, Hg_2^(2+)$ and partially with $P b^{2 +}$ $Pb^(2+)$ cold, to form insoluble compounds, while the salts of nitrate ion are all soluble
So you can have:
$P b {(N O_{3})}_{2} + C l^{-} = P b C l_{2} + N O_{3}^{-}$ $Pb(NO_3)_2 + Cl^(-) = PbCl_2 + NO_3^-$
the molecule $C l_{2}$ $Cl_2$ instead, is a discrete oxidant, but doesn't react neither with $P b^{2 +}$ $Pb^(2+)$ nor with nitrate ion

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