Question #1fb6a

Question

Question #1fb6a

1 Answer

Impact of this question

2906 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-05T13:41:51

$164.086 g / m o l$ $164.086g//mol$

Explanation:

$C a {(N O_{3})}_{2} \Rightarrow C a_{1} {(N_{1} O_{3})}_{2}$ $Ca(NO_3)_2=>Ca_color(red)1(N_color(blue)1O_color(green)3)_color(brown)2$

There are $(1 C a)$ $(color(red)1Ca)$ , $(2 \times 1 N)$ $(color(brown)2xxcolor(blue)1N)$ , $(2 \times 3 O) \Rightarrow 1 C a$ $(color(brown)2xxcolor(green)3O)=>1Ca$ , $2 N$ $2N$ , $6 O$ $6O$

Find molar mass of each (coefficient $\times$ $xx$ atomic mass)

1) $1 C a$ $1Ca$ : $1 \times 40.078 = 40.078 g / m o l$ $1xx40.078=40.078g//mol$

2) $2 N$ $2N$ : $2 \times 14.007 = 28.014 g / m o l$ $2xx14.007=28.014g//mol$

3) $6 O$ $6O$ : $6 \times 15.999 = 95.994 g / m o l$ $6xx15.999=95.994g//mol$

Add all these masses to get the molar mass of $C a {(N O_{3})}_{2}$ $Ca(NO_3)_2$

$40.078 + 28.014 + 95.994 = 164.086 g / m o l$ $40.078+28.014+95.994=164.086g//mol$

Science

Math

Humanities

... and beyond

Question #1fb6a

1 Answer

Explanation:

Related questions

Impact of this question