A $5L$ volume of gas exerts a pressure of $124kPa$ . How should volume evolve if pressure is increased to $206*kPa$ ?

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Answer 1 · 2017-06-10T19:16:33

Well $P_1V_1=P_2V_2$ ....so $V_2=3.0*L$

Old $"Boyle's Law"$ holds that for a given quantity gas, $Pprop1/V$ , and thus $P=k/V$ , where $k$ is some (unspecified!) constant.

And if we solve for $k$ under different conditions of pressure and volume (with temperature CONSTANT!), then.......

$V_2=(P_1xxV_1)/(P_2)=(5*Lxx124*kPa)/(206*kPa)=3.00*L$

Is this answer consistent with the parameters of the problem? Should volume DECREASE with INCREASED pressure?

A 5*L5*L volume of gas exerts a pressure of 124*kPa124*kPa. How should volume evolve if pressure is increased to 206*kPa206*kPa?