Question

Question #aee33

Answer 1

`"46 g Y"`

Explanation:

The idea here is that compound `"XY"` will always contain elements `"X"` and `"Y"` in a

`"2 g X"/"4 g Y" = "1 g X"/"2 g Y"`

mass ratio. In other words, you will always have `"2 g"` of element `"Y"` for every `"1 g"` of element `"X"` present in the sample.

In your case, you know that the second sample contains `"23 g"` of element `"X"`, which means that it must also contain

`23 color(red)(cancel(color(black)("g X"))) * "2 g Y"/(1color(red)(cancel(color(black)("g X")))) = color(darkgreen)(ul(color(black)("46 g Y")))`

I'll leave the answer rounded to two sig figs.