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Answer 1 · 2017-06-16T22:03:12

$C_8H_8O_3$

Empirical Formula of Vanillin

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Answer 2 · 2017-06-16T22:06:05

$C_8H_8O_3$

AS with all these problems, we assume a $100*g$ mass of unknown compound and work out the molar quantities of each element....

$"Moles of carbon"=(63.15*g)/(12.011*g*mol^-1)=5.26*mol$ .

$"Moles of hydrogen"=(5.30*g)/(1.00794*g*mol^-1)=5.26*mol$ .

$"Moles of oxygen"=(31.55*g)/(15.999*g*mol^-1)=1.97*mol$ .

We divide thru by the smallest molar quantity to give a trial empirical formula of........

$C_(2.67)H_(2.67)O_()$ , but if we multiply this by 3 we get.......... $"whole numbers as required. "$

$......................C_8H_8O_3$