At an altitude for which ambient pressure is 0.700*atm, and a temperature of 270.15*K, a balloon contains 3.00*mol of gas... What is the volume of the balloon....?

1 Answer
Jun 18, 2017

There is no question here, but your neighbour, the balloonist, has filled a balloon with approx. 100*L volume.

Explanation:

Of course, he may have heated the contents of the balloon somehow, but we must assume T=270*K, so..........

V=(nRT)/P=(3.00*molxx0.0821*(L*atm)/(K*mol)xx270.15*K)/(0.700*atm)

~=100*L.

We have assumed the temperature, and know that the balloon expanded against a 0.700*atm pressure. Because the balloon is apparently floating, what is the probable filling gas?