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Answer 1 · 2017-06-19T15:08:28

$C_7H_7NO$

As with all of these problems, we assume a $100*g$ mass of unknown compound, and we interrogate its atomic composition...

$"Moles of carbon"=(69.40*g)/(12.011*g*mol^-1)=5.78*mol$ .

$"Moles of hydrogen"=(5.825*g)/(1.00794*g*mol^-1)=5.78*mol$ .

$"Moles of oxygen"=(13.21*g)/(15.999*g*mol^-1)=0.826*mol$ .

$"Moles of nitrogen"=(11.57*g)/(14.01*g*mol^-1)=0.826*mol$ .

And if we divide thru by the SMALLEST molar quantity, i.e. $0.826*mol$ to get a trial empirical formula of......

$C_7H_7NO$ ............