What is the likely identity of a gas at 273.15273.15 KK, whose mass is 7.5*g7.5g, and which exerts a pressure of 1*"bar"1bar?

1 Answer
Jun 19, 2017

Well, let's try to address the molar mass of the gas........we get a range of possibilities.........

Explanation:

"STP"STP specifies a temperature of 273.15 K, and an absolute pressure of exactly 100* kPa, "1 bar".

n=(PV)/(RT)=(1*cancel"bar"xx5.6*cancelL)/(8.314xx10^(-2)cancelL*cancel"bar"*cancel(K^-1)*mol^-1xx273.15*cancelK)

=0.247*(mol^-1)^-1=0.247*mol

And thus (7.5*g)/(0.247*mol)=30.3*g*mol^-1.

The gas is likely the homonuclear diatomic N_2 or O_2.

Further data are needed to confirm the identity of the gas.