How do we formulate the reaction between aluminum and chlorine gas? What is the molar equivalence?

1 Answer
Sep 6, 2017

We wants to make AlCl_3.........

Explanation:

Aluminum metal comes from Group 13 of the Periodic Table; it typically forms the Al^(3+) cation on oxidation......Meanwhile chlorine comes from Group 17. It is typically reduced to give the chloride ion, Cl^-.

And so Al^(3+) + 3xxCl^- and we gets AlCl_3 as the neutral salt; in the solid phase it is probably the chloro-bridged dimer, {Cl_2Al}_2(mu"-"Cl)_2....