Question #7baa6

1 Answer
Jun 21, 2017

Well, we know that 1*mol of Ideal gas at "STP" occupies 22.4*L...

Explanation:

And thus if we assume that carbon dioxide behaves ideally (which is a reasonable assumption, then we have (224*L)/(22.4*L*mol^-1), i.e. a 10*mol quantity of CO_2.....And I think you can see why they specified this particular volume.

And thus there is a 10*mol quantity of carbon, i.e. 10*molxx12.00*g*mol^-1=120.0*g........

And likewise there is 20*molxx15.999*g*mol^-1=320.0*g........with respect to "oxygen".

And you should not have to remember the atomic masses (tho you will soon retain the common masses) because you should be provided with a Periodic Table.