Simplify #2sqrt27+3sqrt12#?

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Answer 1 · 2017-06-22T05:30:08

#2sqrt27+3sqrt12=12sqrt3#

#2# square root of #27# plus #3# square root of #12# can be written as

#2sqrt27+3sqrt12#

= #2sqrt(3xx3xx3)+3sqrt(2xx2xx3)#

= #2sqrt(ul(3xx3)xx3)+3sqrt(ul(2xx2)xx3)#

= #2xx3xxsqrt3+3xx2xxsqrt3#

= #6sqrt3+6sqrt3#

= #(6+6)sqrt3#

= #12sqrt3#