If the boiling point increases by #"0.126 K"# for a solution of a nonelectrolyte in benzene, what molality was required? #K_b = "2.52 K" cdot "kg/mol"#.
1 Answer
Jun 23, 2017
We assume the process is at
The boiling point elevation is given by
#DeltaT_b = T_b - T_b^"*" = iK_bm# ,where:
Benzene is the solvent to this nonelectrolyte. So, the molality is given by
#color(blue)(m) = (DeltaT_b)/(iK_b)#
#~~ (0.126 cancel"K")/(1cdot2.52 cancel"K"cdot"kg/mol")#
#~~# #color(blue)("0.05 mol/kg")#