Question #932c3

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Question #932c3

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Answer 1 · 2017-06-28T16:48:51

$X_{2} Y_{3}$ $X_2Y_3$

Explanation:

Atomic mass of $X$ $X$ = 75
Percentage of $X$ $X$ = 75.8%
Atomic mass of $Y$ $Y$ = 16
Percentage of $Y$ $Y$ = (100-75.8)% = 24.2%

Divide each percentage by the correlating mass:
$X$ $X$ - $\frac{P_{X}}{M_{X}} = \frac{75.8}{75} \approx 1$ $(P_X)/(M_X)=75.8/75~~1$
$Y$ $Y$ - $\frac{P_{Y}}{M_{Y}} = \frac{24.2}{75} \approx 1.5$ $(P_Y)/(M_Y)=24.2/75~~1.5$

The ratio of $X : Y = 1 : 1.5$ $X:Y = 1:1.5$ , but you can't have $\frac{1}{2}$ $1/2$ an atom in a molecule, so the ratio must be doubled so $X : Y = 2 : 3$ $X:Y=2:3$ .

The empirical formula = $X_{2} Y_{3}$ $X_2Y_3$

Proof:
For X - $"Percentage of mass composition" = ("Mass contributuon")/("Total mass")*100 = (2(75))/(2(75)+3(16))*100 = 75.7575... =75.8%$ .
For Y - $"Percentage of mass composition" = ("Mass contributuon")/("Total mass")*100 = (3(16))/(2(75)+3(16))*100 = 24.2424... =24.2%$ .

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Question #932c3

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