What is the pressure in mm*HgmmHg if a 4.0*g4.0g mass of oxygen gas at 303*K303K was confined to a container whose volume of 3000*mL3000mL?

1 Answer
Jun 28, 2017

P=1.04*atm.......

Explanation:

We use the Ideal Gas Equation, to give.....

P=(nRT)/V=((4.00*g)/(32.00*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx303*K)/(3000*mLxx10^-3*L*mL^-1)

=1.04*atm

Now had the pressure been UNDER 1*atm I could use the relationship 1*atm-=760*mm*Hg; i.e. an atmosphere will support a column of mercury that is so high. You do not measure a pressure that is greater than 1*atm in mm*Hg. Whoever set this problem was ignorant.........