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How does aluminum form a complex ion upon oxidation?

1 Answer

Jul 10, 2017

Well have you got $A l^{3 +}$ $Al^(3+)$ or $A l I_{3}$ $AlI_3$ ?

Explanation:

Aluminum does form an complex ion.........

$A l^{3 +} + 4 H O^{-} \to {[A l {(O H)}_{4}]}_{4}^{-}$ $Al^(3+) + 4HO^(-) rarr [Al(OH)_4]^(-)$

From alumina, and this is an important part in (energy-intensive) aluminum refining:

$A l_{2} O_{3} + 2 N a O H \to 2 N a^{+} {[A l O_{2}]}_{2}^{-} + H_{2} O$ $Al_2O_3 + 2NaOH rarr 2Na^(+)[AlO_2]^(-) +H_2O$ .......

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