Question

Question #b50ac

Answer 1

You can add `900` `"mL"` of distilled water.

Explanation:

We're asked to find out how to dilute a `100`-`"mL"` `0.1M` `"HCl"` solution to a concentration of `0.01M`.

We can dilute solutions like this by adding a certain amount of distilled water until it reaches the desired concentration. We therefore need to find out what the final volume of the solution must be to have a concentrationof `0.01M`.

We can use the dilution equation

`M_1V_1 = M_2V_2`

where

• `M_1` and `M_2` are the molarities of the concentrated and dilute solutions, respectively

• `V_1` and `V_2` are the volumes of the concentrated and dilute solutions, respectively

We know:

`M_1 = 0.1M`

`V_1 = 100` `"mL"`

`M_2 = 0.01M`

Plugging these in and solving for `V_2`:

`V_2 = (M_1V_1)/(M_2) = ((0.1cancel(M))(100color(white)(l)"mL"))/(0.01cancel(M)) = 10^3` `"mL"`

Now that we know the necessary plume to attain a concentration of `0.01M`, we subtract the original volume from this to find out how much distilled water must be added:

`10^3` `"mL"` `- 100` `"mL"` `= color(blue)(900` `color(blue)("mL"`