What is the mass of a mole of water?

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What is the mass of a mole of water?

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Answer 1 · 2017-08-25T06:46:04

Well, $18 \cdot g \cdot m o l^{- 1}$ $18*g*mol^-1$ .

Explanation:

Just as $Avogadro's number$ $"Avogadro's number"$ of hydrogen atoms, $^{1} H$ $""^1H$ , has a mass of $1 \cdot g$ $1*g$ . $Avocado's number$ $"Avocado's number"$ of $^{16} O$ $""^16O$ , has a mass of $16 \cdot g$ $16*g$ . And $Avocado's number$ $"Avocado's number"$ of $^{18} O$ $""^18O$ , has a mass of $18 \cdot g$ $18*g$ .

We use $Avogadro's number$ $"Avogadro's number"$ as we would any other collective number, $a dozen$ $"a dozen"$ , $a gross$ $"a gross"$ , etc. Of course $Avogadro's number$ $"Avogadro's number"$ , $6.022 \times 10^{23} \cdot m o l^{- 1}$ $6.022xx10^23*mol^-1$ is absurdly large.

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What is the mass of a mole of water?

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