Question #67a20

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Question #67a20

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Answer 1 · 2017-07-21T14:46:40

B

Explanation:

$Percent of element by mass = \frac{Total mass of element}{Total mass of compound} \cdot 100$ $"Percent of element by mass" = ("Total mass of element")/("Total mass of compound")*100$

For $M_{2} O_{3}$ $M_2O_3$ , we have $53 = \frac{2 M}{2 M + 3 (16)} \cdot 100 = \frac{2 M}{2 M + 48} \cdot 100$ $53=(2M)/(2M+3(16))*100=(2M)/(2M+48)*100$

$\frac{2 M}{2 M + 48} = \frac{53}{100} = 0.53$ $(2M)/(2M+48)=53/100=0.53$

$2 M = 0.53 (2 M + 48) = 1.06 M + 25.44$ $2M=0.53(2M+48)=1.06M+25.44$

$2 M - 1.06 M = 0.94 M$ $2M-1.06M=0.94M$

$0.94 M = 25.44$ $0.94M=25.44$

$M = \frac{25.44}{0.96} = 26.5 \approx 27$ $M=25.44/0.96=26.5~~27$

$27 = B$ $27 = B$

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Question #67a20

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