What molar quantity of gas occupies a volume of #25L# under a pressure of #742kPa# at a temperature of #295*K#?

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Answer 1 · 2017-07-24T19:13:28

WE assume ideality, and we get approx. #8*mol#....

We use the Ideal Gas Equation, and solve for #n#...

#n=(PV)/(RT)=(742*cancel(kPa)xx25*cancelL)/(8.314*(cancelL*cancel(kPa))/(mol*cancelK)*295*cancelK)#

#~=8*1/(mol^-1)=8*1/(1/(mol))=8*mol#

What molar quantity of gas occupies a volume of #25*L# under a pressure of #742*kPa# at a temperature of #295*K#?