What are the sulfur oxidation numbers in $S O_{3} (g)$ $SO_3(g)$ and $S O (g)$ $SO(g)$ ?

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What are the sulfur oxidation numbers in $S O_{3} (g)$ $SO_3(g)$ and $S O (g)$ $SO(g)$ ?

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Answer 1 · 2017-08-01T03:58:26

We gots $sulfur(VI+)$ $"sulfur(VI+)"$ versus $sulfur(+II)$ $"sulfur(+II)"$ ..........

Explanation:

Given the standard rules for assigning oxidation numbers, oxygen generally assumes states of $- I I O$ $stackrel(-II)O$ , and hydrogen $+ I H$ $stackrel(+I)H$ , and it does for these molecules.

And thus the sum of the oxidation numbers equals the charge on the molecule......for sulfuric acid, ..............

$0 = 2 \times + I + 4 \times - I I + S_{oxidation number}$ $0=2xx+I+4xx-II+S_"oxidation number"$ .
Clearly, $S_{oxidation number} = + V I$ $S_"oxidation number"=+VI$ .

And likewise we gots $+ I I S$ $stackrel(+II)S$ in $S O$ $SO$ . $Sulfur monoxide$ $"Sulfur monoxide"$ is an exceptionally rare beast.

What about the oxidation numbers in $H_{2} S O_{3}$ $H_2SO_3$ , $S O_{3}$ $SO_3$ , and $S O_{2}$ $SO_2$ ?

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What are the sulfur oxidation numbers in $S O_{3} (g)$ $SO_3(g)$ and $S O (g)$ $SO(g)$ ?

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What are the sulfur oxidation numbers in $S O_{3} (g)$ $SO_3(g)$ and $S O (g)$ $SO(g)$ ?