What is the $oxidation number$ $"oxidation number"$ of nitrogen in $ammonia, ammonium ion, and nitrate ion$ $"ammonia, ammonium ion, and nitrate ion"$ ?

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What is the $oxidation number$ $"oxidation number"$ of nitrogen in $ammonia, ammonium ion, and nitrate ion$ $"ammonia, ammonium ion, and nitrate ion"$ ?

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Answer 1 · 2017-08-02T05:33:59

We gots $- I I I N$ $stackrel(-III)N$ ..........

Explanation:

While oxidation number is a formalism, it is a convenient formalism. For ions and molecules, the SUM of the oxidation numbers ALWAYS equals the charge on the ion.

TO illustrate, let's take $N H_{3}$ $NH_3$ , $N H_{4}^{+}$ $NH_4^+$ , and $N O_{3}^{-}$ $NO_3^-$ ; now hydrogen and oxygen in their compounds typically take oxidation numbers of $+ I$ $+I$ and $- I I$ $-II$ respectively, and they do here.......

ANd thus for ammonia, $3 \times (+ I) + oxidation number N = 0$ $3xx(+I)+stackrel"oxidation number"N=0$ . Clearly we gots $-III N$ $stackrel"-III"N$ .

And for ammonium, $4 \times (+ I) + oxidation number N = + 1$ $4xx(+I)+stackrel"oxidation number"N=+1$ . Clearly we gots $-III N$ $stackrel"-III"N$ again.

But for nitrate ion, oxygen is MORE electronegative than nitrogen, and it gets the electrons, $3 \times (- I I) + oxidation number N = - 1$ $3xx(-II)+stackrel"oxidation number"N=-1$ . Clearly we gots $+V N$ $stackrel"+V"N$ .

Capisce?

What about $N O$ $NO$ , $N O_{2}$ $NO_2$ , $N_{2} O_{5}$ $N_2O_5$ , $N_{2} O_{4}$ $N_2O_4$ ?

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What is the $oxidation number$ $"oxidation number"$ of nitrogen in $ammonia, ammonium ion, and nitrate ion$ $"ammonia, ammonium ion, and nitrate ion"$ ?

1 Answer

Explanation:

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Science

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Humanities

... and beyond

What is the oxidation number"oxidation number" of nitrogen in ammonia, ammonium ion, and nitrate ion"ammonia, ammonium ion, and nitrate ion"?

1 Answer

Explanation:

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What is the $oxidation number$ $"oxidation number"$ of nitrogen in $ammonia, ammonium ion, and nitrate ion$ $"ammonia, ammonium ion, and nitrate ion"$ ?