Question #46508
1 Answer
Explanation:
We're asked to find the original pressure of the gas, given its initial and final temperatures, and the final pressure.
To do this, we can use the Gay-Lussac's law equation:
(P_1)/(T_1) = (P_2)/(T_2)
where
-
P_1 is the original pressure (what we're trying to find) -
T_1 is the original absolute temperature, which must be in Kelvin:
150 ""^"o""C" + 273 = ul(423color(white)(l)"K"
-
P_2 is the final pressure (456 torr" ) -
T_2 is the final temperature, which is
75.0 ""^"o""C" + 273 = ul(348color(white)(l)"K"
Let's rearrange the equation to solve for the unknown,
P_1 = (T_1P_2)/(T_2)
Plugging in known values, we have
P_1 = ((423cancel("K"))(456color(white)(l)"torr"))/(348cancel("K")) = color(red)(ulbar(|stackrel(" ")(" "554color(white)(l)"torr"" ")|)