Question #f4097
1 Answer
Explanation:
We're asked to find the final pressure of the gas, given its initial pressure, initial temperature, and final temperature.
We can use Gay-Lussac's law for this problem, which is
#ul((P_1)/(T_1) = (P_2)/(T_2))color(white)(aa)# (constant volume and quantity)
where
-
#P_1# is the initial pressure -
#P_2# is the final pressure (what we're trying to find) -
#T_1# is the initial absolute temperature (in Kelvin) -
#T_2# is the final absolute temperature (in Kelvin)
We have:
-
#P_1 = 32.6# #"psi"# -
#P_2 = ?# -
#T_1 = 735# #"K"# -
#T_2 = 1035# #"K"#
Let's rearrange the above equation to solve for the final pressure,
#P_2 = (P_1T_2)/(T_1)#
Plugging in known values:
#P_2 = ((32.6color(white)(l)"psi")(1035cancel("K")))/(735cancel("K")) = color(red)(ulbar(|stackrel(" ")(" "45.9color(white)(l)"psi"" ")|)#
