Question

Question #10d09

Answer 1

77.4%

Explanation:

The percentage of partial ionic character depends upon the difference between the electronegativity of two atoms.

Linus Pauling proposed an empirical relationship which relates the percent ionic character in a bond to the electronegativity difference Δχ:

percent ionic character `= 1−e^((−Δχ/2)^2)xx100`

A commonly used simplified version is:
% ionic character `= 1-exp^(-(0.25)(X_A - X_B)^2)xx100`
http://sciencing.com/figure-ionic-percentage-once-difference-8578423.html

Electronegativity of Ca is 1.0
Electronegativity of O is 3.44
https://www.webelements.com/calcium/electronegativity.html

`(X_A – X_B)^2 = 2.44^2 = 5.95`

% ionic character `= 1-exp^(-(0.25)(5.95))xx100`
% ionic character `= 1-exp^(-1.488)xx100` = `0.774 xx 100 = 77.4%` ionic character.